SAT2化学题型之配对题(Matching questions in Part A)
在每一道SAT2化学配对题型中，给出五个选项来回答所有问题。选项可能是说明性的文字，图画，图表，实验结果，方程式等。有的问题只需要简单的回忆一下知识，有的问题需要对所给信息进行定性或定量的分析来总结出答案。
SAT2化学配对题型的说明特别强调每个选项可以使用一次，多次或者不使用。
PART A
Directions: Every set of the given choices below refers to the numbered statements or formulas immediately following it. Choose the one lettered choice that best fits each statement or formula and then fill in the corresponding oval on the answer sheet. Each choice may be used once, more than once, or not at all in each set.
A部分
说明：前面的一组选项是紧跟其后的几个问题的待选答案。选择出问题的最佳选项，然后涂在答题纸相应位置上。每个选项可以使用一次，多次或者不使用。
例题
Questions 1-3 refer to the following aqueous solutions.
(A) 0.1 M HCl
(B) 0.1 M NaCl
(C) 0.1 M HC2H3O2
(D) 0.1 M CH 3 OH
(E) 0.1 M KOH
1. Is weakly acidic
2. Has the highest pH
3. Reacts with an equal volume of 0.05 M Ba(OH)2 to form a solution with pH = 7
KEY：(C) (E) (A)
SAT2化学题型之判断题 (True/false and relationship questions in Part B)
在实际的SAT2考试中，这种类型的问题要求把答案写在标有“化学”的专用的答题纸上。第二种类型的题目从101道题目开始。每道题目的第一栏有一种表述，另一边的第二栏有另一种表述。你的首要任务是判断这些表述是否正确，并在答题纸上相应位置选择T或F;然后运用推理能力和对题目的理解判断两种表述是否存在因果关系。所以说小编提醒大家注意在备考中一定要慢慢总结SAT2化学原理，重视SAT2考试中对于词汇的考察。
Part B
Directions: Every question below contains two statements, Ⅰin the left-hand column and Ⅱ in the right-hand column. For each question, decide if statementⅠis true or false and if statementⅡis true or false and fill in the corresponding T or F ovals on your answer sheet. Fill in oval CE only if state Ⅱis a correct explanation of statement Ⅰ.
说明：下面的每个问题包括两种表述，左栏的Ⅰ和右栏的Ⅱ。对于每一个问题，判断Ⅰ和Ⅱ的表述是否正确，并在答题纸上相应位置选择T或F。当Ⅱ是Ⅰ的正确解释时填涂CE。
Sample Answer Grid:
CHEMISTRY* Fill in oval CE if only Ⅱis a correct explanation of Ⅰ.
EXAMPLE
The reaction that takes place is
Ⅰ Ⅱ
101. When 2 liters of oxygen gas react completely with 2 liters of hydrogen gas, the limiting factor is the volume of the oxygen . BECAUSE The coefficients in the balanced equation of a gaseous reaction give the volume relationship of the reacting gases.
Ⅰ Ⅱ
101. 2升氧气与2升氢气充分反应，限制因素是氧气的量因为配平的反应方程式的各个反应物的系数表明了参加反应的气体之间量的关系
反应的化学方程式为
2H2 + O2 → 2H2O
The coefficient of this gaseous reaction show that 2L of hydrogen react with 1L of oxygen, leaving 1L of unreacted oxygen. The limiting factor is the quantity of hydrogen.
气体反应的系数表明2L氢气与1L氧气反应，剩余1L氧气未参加反应。 限制因素应是氢气的量。
The ability to solve this quantitative relationship shows that statement I is not true. However, statement II does give a true statement of the relationship of coefficients in a balanced equation of gaseous chemical reaction. Therefore, you should fill F in I and T in II.
定量结果表明I 是不正确的。但是，II 所表述的.配平的反应方程式的各个反应物的系数表明了参加反应的气体之间量的关系是对的。因此，在I中选择F，II中选择T。
SAT2化学题型之多项选择题(General multiple-choice question in Part C)
这个SAT2化学题型通常为问题或者不完整表述，带有五个备选答案，你必须从中选出最佳答案。在有些题目中，要求选出不恰当的答案。这种问题包括大写的单词,例如NOT, LEAST, EXCEPT。
在有的问题中，会要求在图片，图表，数学表达式和文字表述之间建立联系。解决方法包括对已知信息的正确解读来解决科学问题。有时同一信息可以用来解答两个或更多的问题。
PART C
Direction: Every question or incomplete statement below is followed by five suggested answers or completions. Choose the one that is best in each case and then fill in the corresponding oval on answer sheet.
说明：下面的每个问题或不完整表述都带有五个备选答案。选出最佳答案并填写在答题纸的相应位置上。
EXAMPLE：
If the molar mass of NH 3 is 17g/mol, what is the density of this compound at STP?
1. 0.25g/L 2. 0.76g/L 3. 1.25g/L 4. 3.04g/L 5. 9.11g/L
The solution of this quantitative problem depends on the application of several principles. One principle is that the molar mass of a gas expressed in grams/mole will occupy 22.4L at standard temperature and pressure (STP). The other is that the density of a gas at STP is the mass of 1L of the gas. Therefore, 17g of ammonia (NH 3) will occupy 22..4L, and 1L is equal to 17g/22.4L or 0.76g/L. The correct answer is (B).
如果(NH 3)的分子质量是17g/mol, 在标准状况下这种化合物的密度是多少?
1. 0.25g/L 2. 0.76g/L 3. 1.25g/L 4. 3.04g/L 5. 9.11g/L
这个定量问题的解决需要运用几个原理。其中之一是在标准状况下(STP)一摩尔气体所占的体积是22.4升。另一原理是在STP气体的密度为1L气体的质量。因此，1mol氨气的体积为22.4升，1L质量就是17/22.4 g或者0.76 g。正确答案为(B)。